Evaluate $32^{x-3}$ x $8^{x+4}$ = $\frac{64}{2^2}$

      

Evaluate $32^{x-3}$ x $8^{x+4}$ = $\frac{64}{2^x}$

  

Answers

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$32^{x-3}$ x $8^{x+4}$ = $\frac{64}{2^x}$

$2^{5(x-3)}$ x $2^{3(x+4)}$ = $2^6 \times (2)^{-x}$

5x - 15 + 3x + 12 = 6 - x

8x - 3 = 6 - x

9x = 9;

x = 1

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johnmulu answered the question on June 12, 2017 at 08:12

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